United States presidential election in Vermont, 1916

United States presidential election in Vermont, 1916

← 1912 November 7, 1916 1920 →
Nominee Charles E. Hughes Woodrow Wilson Party Republican Democratic Home state New York New Jersey Running mate Charles W. Fairbanks Thomas R. Marshall Electoral vote 4 0 Popular vote 40,250 22,708 Percentage 62.43% 35.22%
County Results   Wilson—50-60%   Hughes—50-60%   Hughes—60-70%   Hughes—70-80%
President before election Woodrow Wilson Democratic Elected President Woodrow Wilson Democratic

Woodrow Wilson
Democratic

Woodrow Wilson
Democratic

The 1916 United States Presidential Election in Vermont took place on November 7, 1916 as part of the 1916 United States Presidential Election which was held throughout all contemporary 48 states. Voters chose 4 representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont was won by the Republican nominee, U.S. Supreme Court Justice Charles Evans Hughes of New York, and his running mate Senator Charles W. Fairbanks of Indiana. Hughes and Fairbanks defeated the Democratic nominees, incumbent Democratic President Woodrow Wilson and Vice President Thomas R. Marshall.

Hughes won a decisive victory with 62.43% of the vote, to Wilson's 35.22%, a Republican victory margin of 27.21%.

Vermont historically was a bastion of liberal Northeastern Republicanism, and by 1916 the Green Mountain State had gone Republican in every presidential election since the founding of the Republican Party. From 1856 to 1912, Vermont had had the longest streak of voting Republican of any state, having never voted Democratic before, and this tradition continued in 1916.