United States presidential election in Vermont, 1912

← 1908

November 5, 1912

1916 →


Nominee	William H. Taft	Theodore Roosevelt	Woodrow Wilson
Party	Republican	Progressive	Democratic
Home state	Ohio	New York	New Jersey
Running mate	Nicholas M. Butler (replacing James S. Sherman)	Hiram Johnson	Thomas R. Marshall
Electoral vote	4	0	0
Popular vote	23,332	22,132	15,354
Percentage	37.13%	35.22%	24.43%

County Results

Taft

<40%

40-50%

Roosevelt

<40%

40-50%

Wilson

<40%

President before election

William Howard Taft
Republican

Elected President

Woodrow Wilson
Democratic

Taft

Roosevelt

Wilson

William Howard Taft
Republican

The 1912 United States Presidential Election in Vermont took place on November 5, 1912 as part of the 1912 United States Presidential Election which was held throughout all contemporary 48 states. Voters chose 4 representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont was won by the Republican nominees, incumbent President William Howard Taft, and his running mate Vice President James S. Sherman. Taft and Sherman defeated the Progressive Party candidates, former President Theodore Roosevelt and his running mate California Governor Hiram Johnson, and the Democratic nominees, New Jersey Governor Woodrow Wilson and Indiana Governor Thomas R. Marshall.