United States presidential election in Wisconsin, 1988

United States presidential election in Wisconsin, 1988

← 1984 November 8, 1988 1992 →
Nominee Michael Dukakis George H. W. Bush Party Democratic Republican Home state Massachusetts Texas Running mate Lloyd Bentsen Dan Quayle Electoral vote 11 0 Popular vote 1,126,794 1,047,499 Percentage 51.41% 47.80%
County Results   Dukakis—70-80%   Dukakis—60-70%   Dukakis—50-60%   Bush—50-60%   Bush—60-70%   Bush—70-80%
President before election Ronald Reagan Republican Elected President George H. W. Bush Republican

Ronald Reagan
Republican

George H. W. Bush
Republican

The 1988 United States presidential election in Wisconsin took place on November 8, 1988. All 50 states and the District of Columbia, were part of the 1988 United States presidential election. Wisconsin voters chose 11 electors to the Electoral College, which selected the President and Vice President.

Wisconsin was won by Massachusetts Governor Michael Dukakis who was running against incumbent United States Vice President George H. W. Bush of Texas. Dukakis ran with Texas Senator Lloyd Bentsen as Vice President, and Bush ran with Indiana Senator Dan Quayle.

Wisconsin weighed in for this election as 12% more Democratic than the national average.

The presidential election of 1988 was a very partisan election for Wisconsin, with over 99% of the electorate voting for either the Republican or Democratic parties.

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