United States presidential election in Wisconsin, 1992

United States presidential election in Wisconsin, 1992

← 1988 November 3, 1992 1996 →
Nominee Bill Clinton George H.W. Bush Ross Perot Party Democratic Republican Independent Home state Arkansas Texas Texas Running mate Al Gore Dan Quayle Electoral vote 11 0 0 Popular vote 1,041,066 930,855 544,479 Percentage 41.1% 36.8% 21.5%
County Results   Clinton—>70%   Clinton—60-70%   Clinton—50-60%   Clinton—40-50%   Bush—40-50%   Bush—50-60%   Bush—60-70%   Bush—>70%
President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

George H. W. Bush
Republican

Bill Clinton
Democratic

The 1992 United States presidential election in Wisconsin took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose eleven representatives, or electors to the Electoral College, who voted for President and Vice President.

Wisconsin was won by Governor Bill Clinton (D-Arkansas) with 41.13% of the popular vote over incumbent President George H.W. Bush (R-Texas) with 36.78%. Businessman Ross Perot (I-Texas) finished in third with 21.51% of the popular vote. Clinton ultimately won the national vote, defeating incumbent President Bush.