United States presidential election in Washington, 1988

United States presidential election in Washington, 1988

← 1984 November 8, 1988 1992 →
Nominee Michael Dukakis George H. W. Bush Party Democratic Republican Home state Massachusetts Texas Running mate Lloyd Bentsen Dan Quayle Electoral vote 10 0 Popular vote 933,516 903,835 Percentage 50.05% 48.46%
County Results   Dukakis—60-70%   Dukakis—50-60%   Dukakis—<50%   Tie—<50%   Bush—<50%   Bush—50-60%   Bush—60-70%
President before election Ronald Reagan Republican Elected President George H. W. Bush Republican

Ronald Reagan
Republican

George H. W. Bush
Republican

The 1988 United States presidential election in Washington took place on November 8, 1988. All 50 states and the District of Columbia, were part of the 1988 United States presidential election. Washington voters chose 10 electors to the Electoral College, which selected the President and Vice President.

Washington was won by Democratic Massachusetts Governor Michael Dukakis, who was running against incumbent Republican Vice President George H. W. Bush of Texas. Dukakis ran with Texas Senator Lloyd Bentsen, and Bush ran with Indiana Senator Dan Quayle.

Dukakis carried Washington state with 50.05% of the vote to Bush's 48.46%, a margin of 1.59%. This made Washington one of 10 states (along with the District of Columbia) to vote for Dukakis, even as Bush won a convincing victory nationally.