United States presidential election in Washington, 1992

United States presidential election in Washington, 1992

1988 ← November 3, 1992 → 1996

Nominee Bill Clinton George H.W. Bush Ross Perot Party Democratic Republican Independent Home state Arkansas Texas Texas Running mate Al Gore Dan Quayle Electoral vote 11 0 0 Popular vote 993,037 731,234 541,780 Percentage 43.4% 32.0% 23.7%

County Results   Clinton—>70%   Clinton—60-70%   Clinton—50-60%   Clinton—40-50%   Bush—40-50%   Bush—50-60%   Bush—60-70%   Bush—>70%   Perot—40-50%

President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

George H. W. Bush
Republican

Bill Clinton
Democratic

The 1992 United States presidential election in Washington took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose eleven representatives, or electors to the Electoral College, who voted for President and Vice President.

Washington was won by Governor Bill Clinton (D-Arkansas) with 43.41% of the popular vote over incumbent President George H.W. Bush (R-Texas) with 31.97%. Businessman Ross Perot (I-Texas) finished in third with 23.68% of the popular vote. Clinton ultimately won the national vote, defeating incumbent President Bush.