United States presidential election in Vermont, 1940

United States presidential election in Vermont, 1940

← 1936 November 5, 1940 1944 →
Nominee Wendell Willkie Franklin D. Roosevelt Party Republican Democratic Home state Indiana New York Running mate Charles L. McNary Henry A. Wallace Electoral vote 3 0 Popular vote 78,371 64,269 Percentage 54.78% 44.92%
County Results   Roosevelt—50-60%   Willkie—50-60%   Willkie—60-70%
President before election Franklin D. Roosevelt Democratic Elected President Franklin D. Roosevelt Democratic

Franklin D. Roosevelt
Democratic

Franklin D. Roosevelt
Democratic

The 1940 United States Presidential Election in Vermont took place on November 5, 1940 as part of the 1940 United States Presidential Election which was held throughout all contemporary 48 states. Voters chose 3 representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont voted for the Republican nominee, corporate lawyer Wendell Willkie of Indiana, over the Democratic nominee, incumbent President Franklin D. Roosevelt of New York. Willkie's running mate was Senate Minority Leader Charles L. McNary of Oregon, while Roosevelt ran with Secretary of Agriculture Henry A. Wallace of Iowa.

Willkie took 54.78% of the vote, to Roosevelt's 44.92%, a margin of 9.86%.

Vermont historically was a bastion of liberal Northeastern Republicanism, and by 1940 the Green Mountain State had gone Republican in every presidential election since the founding of the Republican Party. From 1856 to 1936, Vermont had had the longest streak of voting Republican of any state, having never voted Democratic before, and this tradition continued in 1940.