United States presidential election in Vermont, 1928

United States presidential election in Vermont, 1928

← 1924 November 6, 1928 1932 →
Nominee Herbert Hoover Al Smith Party Republican Democratic Home state California New York Running mate Charles Curtis Joseph T. Robinson Electoral vote 4 0 Popular vote 90,404 44,440 Percentage 66.87% 32.87%
County Results   Smith—50-60%   Hoover—50-60%   Hoover—60-70%   Hoover—70-80%   Hoover—80-90%
President before election Calvin Coolidge Republican Elected President Herbert Hoover Republican

Calvin Coolidge
Republican

Herbert Hoover
Republican

The 1928 United States Presidential Election in Vermont took place on November 6, 1928 as part of the 1928 United States Presidential Election which was held throughout all contemporary 48 states. Voters chose 4 representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont voted for the Republican nominee, Secretary of Commerce Herbert Hoover of California, over the Democratic nominee, Governor Alfred E. Smith of New York. Hoover's running mate was Senate Majority Leader Charles Curtis of Kansas, while Smith ran with Senator Joseph Taylor Robinson of Arkansas.

Hoover took 66.87% of the vote, to Smith's 32.87%, a margin of 34.00%.

Vermont historically was a bastion of liberal Northeastern Republicanism, and by 1928 the Green Mountain State had gone Republican in every presidential election since the founding of the Republican Party. From 1856 to 1924, Vermont had had the longest streak of voting Republican of any state, having never voted Democratic before, and this tradition continued amidst a third consecutive nationwide Republican landslide in 1928.