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United States presidential election in Michigan, 1988

United States presidential election in Michigan, 1988
Michigan
← 1984 November 8, 1988 1992 →
  George H. W. Bush, Vice President of the United States, official portrait.jpg Dukakis1988rally cropped.jpg
Nominee George H. W. Bush Michael Dukakis
Party Republican Democratic
Home state Texas Massachusetts
Running mate Dan Quayle Lloyd Bentsen
Electoral vote 20 0
Popular vote 1,965,486 1,675,783
Percentage 53.6% 45.7%

MN1988.jpg
County Results
  Dukakis—70-80%
  Dukakis—60-70%
  Dukakis—50-60%
  Bush—50-60%
  Bush—60-70%
  Bush—70-80%

President before election

Ronald Reagan
Republican

Elected President

George H. W. Bush
Republican


Ronald Reagan
Republican

George H. W. Bush
Republican

The 1988 United States presidential election in Michigan took place on November 8, 1988. All 50 states and the District of Columbia, were part of the 1988 United States presidential election. Michigan voters chose 20 electors to the Electoral College, which selected the President and Vice President.

Michigan was won by incumbent United States Vice President George H. W. Bush of Texas, who was running against Massachusetts Governor Michael Dukakis. Bush ran with Indiana Senator Dan Quayle as Vice President, and Dukakis ran with Texas Senator Lloyd Bentsen.

Michigan weighed in for this election as 0.1% more Republican than the national average. This was the last time that the state of Michigan would be won by a Republican presidential candidate until 2016.


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