United States presidential election in Michigan, 1992

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November 3, 1992

1996 →


Nominee	Bill Clinton	George H.W. Bush	Ross Perot
Party	Democratic	Republican	Independent
Home state	Arkansas	Texas	Texas
Running mate	Al Gore	Dan Quayle
Electoral vote	18	0	0
Popular vote	1,871,182	1,554,940	824,813
Percentage	43.8%	36.4%	19.3%

County results

Clinton

30-39%

40-49%

50-59%

60-69%

Bush

30-39%

40-49%

50-59%

President before election

George H. W. Bush
Republican

Elected President

Bill Clinton
Democratic

Clinton

Bush

George H. W. Bush
Republican

Bill Clinton
Democratic

The 1992 United States presidential election in Michigan took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose eighteen representatives, or electors to the Electoral College, who voted for President and Vice President.

Michigan was won by Governor Bill Clinton (D-Arkansas) with 43.77% of the popular vote over incumbent President George H.W. Bush (R-Texas) with 36.38%. Businessman Ross Perot (I-Texas) finished in third with 19.30% of the popular vote. Clinton ultimately won the national vote, defeating incumbent President Bush. This was the first time that a Democratic presidential candidate carried Michigan since 1968.

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