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United States presidential election in Vermont, 1836

United States presidential election in Vermont, 1836
Vermont
← 1832 November 3 - December 7, 1836 1840 →
  William Henry Harrison by James Reid Lambdin, 1835-crop.jpg MVanBuren.png
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate Francis Granger Richard Mentor Johnson
Electoral vote 7 0
Popular vote 35,031 14,037
Percentage 59.93 40.07

President before election

Andrew Jackson
Democratic

Elected President

Martin Van Buren
Democratic


Andrew Jackson
Democratic

Martin Van Buren
Democratic


The 1836 United States presidential election in Vermont took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont voted for Whig candidate William Henry Harrison over Democratic candidate Martin Van Buren. Harrison won Vermont by a margin of 19.86%.


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