United States presidential election in Ohio, 1988
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County Results
Dukakis—60-70%
Dukakis—50-60%
Bush—50-60%
Bush—60-70%
Bush—70-80%
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The 1988 United States presidential election in Ohio took place on November 8, 1988. All 50 states and the District of Columbia, were part of the 1988 United States presidential election. Ohio voters chose 23 electors to the Electoral College, which selected the President and Vice President.
Ohio was won by incumbent United States Vice President George H. W. Bush of Texas, who was running against Massachusetts Governor Michael Dukakis. Bush ran with Indiana Senator Dan Quayle as Vice President, and Dukakis ran with Texas Senator Lloyd Bentsen.
Ohio weighed in for this election as 2% more Republican than the national average.
The presidential election of 1988 was a very partisan election for Ohio, with more than 99% of the electorate voting for either the Democratic or Republican parties. Most counties in the state turned out more for Bush than Dukakis. Two notable exceptions to this trend were Cleveland's Cuyahoga County, and residents of several counties on the Eastern border with Pennsylvania, who voted largely for Dukakis.
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