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United States presidential election in Nebraska, 1988

United States presidential election in Nebraska, 1988
Nebraska
1984 ←
November 8, 1988 → 1992

  George H. W. Bush, Vice President of the United States, official portrait.jpg Dukakis1988rally cropped.jpg
Nominee George H. W. Bush Michael Dukakis
Party Republican Democratic
Home state Texas Massachusetts
Running mate Dan Quayle Lloyd Bentsen
Electoral vote 5 0
Popular vote 398,447 259,646
Percentage 60.2% 39.2%

NE1988.jpg

County Results
  Dukakis—50-60%
  Bush—<50%
  Bush—50-60%
  Bush—60-70%
  Bush—70-80%
  Bush—80-90%

President before election

Ronald Reagan
Republican

Elected President

George H. W. Bush
Republican


NE1988.jpg

Ronald Reagan
Republican

George H. W. Bush
Republican

The 1988 United States presidential election in Nebraska took place on November 8, 1988. All 50 states and the District of Columbia, were part of the 1988 United States presidential election. Nebraska voters chose 5 electors to the Electoral College, which selected the President and Vice President.

Nebraska was won by incumbent United States Vice President George H. W. Bush of Texas, who was running against Massachusetts Governor Michael Dukakis. Bush ran with Indiana Senator Dan Quayle as Vice President, and Dukakis ran with Texas Senator Lloyd Bentsen.


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