United States presidential election in Missouri, 1988
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County Results
Dukakis—70-80%
Dukakis—60-70%
Dukakis—50-60%
Bush—50-60%
Bush—60-70%
Bush—70-80%
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The 1988 United States presidential election in Missouri took place on November 8, 1988. All 50 states and the District of Columbia, were part of the 1988 United States presidential election. Missouri voters chose 11 electors to the Electoral College, which selected the President and Vice President.
Missouri was won by incumbent United States Vice President George H. W. Bush of Texas, who was running against Massachusetts Governor Michael Dukakis. Bush ran with Indiana Senator Dan Quayle as Vice President, and Dukakis ran with Texas Senator Lloyd Bentsen.
Missouri weighed in for this election as 2% more Democratic than the national average.
The presidential election of 1988 was a very partisan election for Missouri, with more than 99% of the electorate voting for either the Democratic or Republican parties, and only three parties total appearing on the ballot. In typical form for the time, the more rural counties in Missouri turned out for the Republican candidate, while the more populated centers of the city of St. Louis (though, notably, not St. Louis County), and East Kansas City, voted overwhelmingly Democratic.
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