United States presidential election in Kentucky, 1988
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County Results
Dukakis—70-80%
Dukakis—60-70%
Dukakis—50-60%
Bush—50-60%
Bush—60-70%
Bush—70-80%
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The 1988 United States presidential election in Kentucky took place on November 8, 1988. All 50 states and the District of Columbia, were part of the 1988 United States presidential election. Kentucky voters chose 9 electors to the Electoral College, which selected the President and Vice President.
Kentucky was won by incumbent United States Vice President George H. W. Bush of Texas, who was running against Massachusetts Governor Michael Dukakis. Bush ran with Indiana Senator Dan Quayle as Vice President, and Dukakis ran with Texas Senator Lloyd Bentsen.
Kentucky weighed in for this election as 2% more Republican than the national average.
The 1988 presidential election is also the last time that Kentucky voted for a different presidential candidate from neighbouring West Virginia.
The presidential election of 1988 was a very partisan election for Kentucky, with more than 99% of the electorate voting for either the Democratic or Republican parties, and only five parties appearing on the ballot. The vast majority of counties turned out for Bush, including the highly populated center of Louisville's Jefferson County. Conversely, several small clumps of counties in the far Eastern (surrounding Pike County) and in the far Western (surrounding McCracken County) regions of the state voted primarily Democratic.
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