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United States presidential election in Hawaii, 1988

United States presidential election in Hawaii, 1988
Hawaii
← 1984 November 8, 1988 1992 →
  Dukakis1988rally cropped.jpg George H. W. Bush, Vice President of the United States, official portrait.jpg
Nominee Michael Dukakis George H. W. Bush
Party Democratic Republican
Home state Massachusetts Texas
Running mate Lloyd Bentsen Dan Quayle
Electoral vote 4 0
Popular vote 192,364 158,625
Percentage 54.3% 44.8%

United States presidential election in Hawaii, 1976 & 1988 results by county.svg
Dukakis
  50-60%

President before election

Ronald Reagan
Republican

Elected President

George H. W. Bush
Republican


Ronald Reagan
Republican

George H. W. Bush
Republican

The 1988 United States presidential election in Hawaii took place on November 8, 1988. All 50 states and the District of Columbia, were part of the 1988 United States presidential election. Hawaii voters chose 4 electors to the Electoral College, which selected the President and Vice President.

Hawaii was won by Massachusetts Governor Michael Dukakis who was running against incumbent United States Vice President George H. W. Bush of Texas. Dukakis ran with Texas Senator Lloyd Bentsen as Vice President, and Bush ran with Indiana Senator Dan Quayle.

Hawaii weighed in for this election as 9% more Democratic than the national average.

The presidential election of 1988 was a very partisan election for Hawaii, with 99% of the electorate voting for either the Democratic or Republican parties. All four of the Hawaiian island districts voted in majority for Dukakis.


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