United States presidential election in Georgia, 1992

United States presidential election in Georgia, 1992

1988 ← November 3, 1992 → 1996

Nominee Bill Clinton George H. W. Bush Ross Perot Party Democratic Republican Independent Home state Arkansas Texas Texas Running mate Al Gore Dan Quayle Electoral vote 13 0 0 Popular vote 1,008,966 995,252 309,657 Percentage 43.5% 42.9% 13.3%

County Results   Clinton—70-80%   Clinton—60-70%   Clinton—50-60%   Clinton—40-50%   Clinton—<40%   Tie Clinton/Bush—<50%   Bush—<40%   Bush—40-50%   Bush—50-60%

President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

George H. W. Bush
Republican

Bill Clinton
Democratic

The 1992 United States presidential election in Georgia took place on November 3, 1992 throughout all 50 states and D.C., which was part of the 1992 United States presidential election. Voters chose 13 representatives, or electors to the Electoral College, who voted for President and Vice President.

Georgia was won by Governor Bill Clinton (D-AR). The presidential contest in the Peach state was the closest of any state that year with Clinton winning 43.47% to 42.88% over Incumbent President George H. W. Bush (R) by a razor thin margin of 0.59%. This made it the first time that Georgia had voted Democratic since 1980, when it voted for Jimmy Carter, who was the former Governor. The state has remained Republican since this election. From the mid-1960s until about the early 1990s, Georgia was a swing state in presidential elections, but also a state in which Democrats generally dominated congressional and state and local elections. Billionaire Businessman Ross Perot (I-TX) finished in third with a significant 13.34% of the popular vote in the Peach state. This is the last time that Democrats would carry Georgia's electoral votes in a presidential election. Following this election Georgia would gradually become a 'red state' following the Republican Revolution of 1994.