United States presidential election in Alabama, 1992

United States presidential election in Alabama, 1992

← 1988 November 3, 1992 1996 →
Nominee George H.W. Bush Bill Clinton Ross Perot Party Republican Democratic Independent Home state Texas Arkansas Texas Running mate Dan Quayle Al Gore Electoral vote 9 0 0 Popular vote 804,283 690,080 183,109 Percentage 47.7% 40.9% 10.9%
County Results   Clinton—>70%   Clinton—60-70%   Clinton—50-60%   Clinton—40-50%   Bush—40-50%   Bush—50-60%   Bush—60-70%   Bush—>70%   Perot—40-50%
President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

George H. W. Bush
Republican

Bill Clinton
Democratic

The 1992 United States presidential election in Alabama took place on November 3, 1992 throughout all 50 states and D.C., which was part of the 1992 United States presidential election. Voters chose 9 representatives, or electors to the Electoral College, who voted for President and Vice President.

Alabama was won by President George H.W. Bush (R-TX). The presidential contest in Alabama was not a surprise, with Bush winning 47.65% to 40.88% over Governor Bill Clinton (D), a margin of 7.77%. Despite the fact that Clinton was a Southern Democrat, Alabama remained a reliably Republican state. The last Democrat to carry Alabama was Jimmy Carter in 1976, who was also a Southern Democrat. Billionaire businessman Ross Perot (I-TX) finished in third with a disappointing 10.85%, a good amount but not the desired amount wanted by Perot. Alabama has stayed a Republican state since then, with no major Democratic charge by any contender since then.