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Simonton Lake, Indiana

Simonton Lake, Indiana
Census-designated place
Elkhart County Indiana Incorporated and Unincorporated areas Simonton Lake Highlighted.svg
Coordinates: 41°44′45″N 85°58′17″W / 41.74583°N 85.97139°W / 41.74583; -85.97139Coordinates: 41°44′45″N 85°58′17″W / 41.74583°N 85.97139°W / 41.74583; -85.97139
Country United States
State Indiana
County Elkhart
Area
 • Total 4.1 sq mi (10.5 km2)
 • Land 3.6 sq mi (9.2 km2)
 • Water 0.5 sq mi (1.2 km2)
Elevation 787 ft (240 m)
Population (2010)
 • Total 4,678
 • Density 1,200/sq mi (450/km2)
Time zone Eastern (EST) (UTC-5)
 • Summer (DST) EDT (UTC-4)
FIPS code 18-69840
GNIS feature ID 0452104

Simonton Lake is a census-designated place (CDP) in Elkhart County, Indiana, United States. The population was 4,678 at the 2010 census.

The community takes its name from the lake. Simonton Lake was named for Samuel Simonton, a 19th-century farmer.

Simonton Lake is located at 41°44′45″N 85°58′17″W / 41.74583°N 85.97139°W / 41.74583; -85.97139 (41.745799, -85.971499).

According to the United States Census Bureau, the CDP has a total area of 4.1 square miles (10.5 km2), of which 3.6 square miles (9.2 km2) is land and 0.46 square miles (1.2 km2), or 11.68%, is water.

As of the census of 2000, there were 4,053 people, 1,567 households, and 1,181 families residing in the CDP. The population density was 1,243.0 people per square mile (480.0/km²). There were 1,636 housing units at an average density of 501.7/sq mi (193.8/km²). The racial makeup of the CDP was 94.77% White, 1.63% African American, 0.25% Native American, 1.55% Asian, 0.64% from other races, and 1.16% from two or more races. Hispanic or Latino of any race were 2.52% of the population.


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