Seymour, Missouri
| Seymour, Missouri | |
|---|---|
| City | |
Seymour Square, looking South, 2006
|
|
 Location of Seymour in Webster County and Missouri |
|
| Coordinates: 37°8′52″N 92°46′8″W / 37.14778°N 92.76889°WCoordinates: 37°8′52″N 92°46′8″W / 37.14778°N 92.76889°W | |
| Country | United States |
| State | Missouri |
| County | Webster |
| Area | |
| • Total | 2.76 sq mi (7.15 km2) |
| • Land | 2.76 sq mi (7.15 km2) |
| • Water | 0 sq mi (0 km2) |
| Population (2010) | |
| • Total | 1,921 |
| • Estimate (2012) | 1,928 |
| • Density | 696.0/sq mi (268.7/km2) |
| Time zone | Central (CST) (UTC-6) |
| • Summer (DST) | CST (UTC-5) |
| Website | Official website |
Seymour is a city in Webster County, Missouri, United States. The population was 1,921 at the 2010 census. It is part of the Springfield, Missouri Metropolitan Statistical Area.
Seymour was laid out in 1882. The community's name is a transfer from Seymour, Indiana. A post office called Seymour has been in operation since 1881.
The Col. Thomas C. Love House was listed on the National Register of Historic Places in 1985.
Seymour is located at 37°8′52″N 92°46′8″W / 37.14778°N 92.76889°W (37.147671, -92.768882). According to the United States Census Bureau, the city has a total area of 2.76 square miles (7.15 km2), all of it land. Seymour is located on the southeastern edge of the Springfield Plateau in the Ozark Mountains.
As of the census of 2010, there were 1,921 people, 746 households, and 510 families residing in the city. The population density was 696.0 inhabitants per square mile (268.7/km2). There were 846 housing units at an average density of 306.5 per square mile (118.3/km2). The racial makeup of the city was 95.5% White, 0.3% African American, 1.0% Native American, 0.3% Asian, 0.1% Pacific Islander, 0.7% from other races, and 2.1% from two or more races. Hispanic or Latino of any race were 2.8% of the population.
...
Wikipedia