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Mahopac, New York

Mahopac, New York
Census-designated place & hamlet
Location in Putnam County and the state of New York.
Location in Putnam County and the state of New York.
Coordinates: 41°22′11″N 73°44′15″W / 41.36972°N 73.73750°W / 41.36972; -73.73750Coordinates: 41°22′11″N 73°44′15″W / 41.36972°N 73.73750°W / 41.36972; -73.73750
Country United States
State New York
County Putnam
Area
 • Total 6.4 sq mi (16.7 km2)
 • Land 5.3 sq mi (13.7 km2)
 • Water 1.1 sq mi (2.9 km2)
Elevation 666 ft (203 m)
Population (2010)
 • Total 8,369
 • Density 1,300/sq mi (500/km2)
Time zone Eastern (EST) (UTC-5)
 • Summer (DST) EDT (UTC-4)
ZIP code 10541
Area code(s) 845
FIPS code 36-44534
GNIS feature ID 0956273

Mahopac (/ˈmˌpæk/ or /ˈmɑː.hˌpæk/) is a hamlet (and census-designated place) in the town of Carmel in Putnam County, New York. An exurb some 47 miles (76 km) north of New York City, Mahopac is located on US Route 6 on the county's southern central border with Westchester County. As of the 2010 census, the population was 8,369.

Mahopac and Mahopac Falls have played central roles in the history of Putnam County.

Originally inhabited by the Wappinger Native Americans, an Algonquian tribe, the hamlet's land was patented in 1697 by Adolphus Philipse, son of a wealthy Anglo-Dutch gentryman. During the French and Indian War, Wappingers throughout Putnam County traveled north to Massachusetts to fight for the British.


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