Holland, Brown County, Wisconsin
| Holland, Wisconsin | |
|---|---|
| Town | |
Town hall for Holland
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 Location in Brown County and the state of Wisconsin. |
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| Coordinates: 44°16′21″N 88°7′35″W / 44.27250°N 88.12639°W | |
| Country | United States |
| State | Wisconsin |
| County | Brown |
| Area | |
| • Total | 3 sq mi (93.2 km2) |
| • Land | 3 sq mi (93.2 km2) |
| • Water | 0.0 sq mi (0.0 km2) |
| Elevation | 768 ft (234 m) |
| Population (2010) | |
| • Total | 1,519 |
| • Density | 42/sq mi (16.3/km2) |
| Time zone | Central (CST) (UTC-6) |
| • Summer (DST) | CDT (UTC-5) |
| Area code(s) | 920 |
| FIPS code | 55-35325 |
| GNIS feature ID | 1583400 |
| Website | www |
Holland is a town in Brown County in the U.S. state of Wisconsin. The population was 1,519 at the 2010 census. The unincorporated communities of Askeaton and Hollandtown are located in the town.
Holland occupies the southwest corner of Brown County, with Outagamie County to the west and Calumet and Manitowoc counties to the south.
According to the United States Census Bureau, the town has a total area of 36.0 square miles (93.2 km2), all of it land.
As of the census of 2000, there were 1,339 people, 433 households, and 352 families residing in the town. The population density was 37.2 people per square mile (14.4/km²). There were 444 housing units at an average density of 12.3 per square mile (4.8/km²). The racial makeup of the town was 98.58% White, 0.07% African American, 0.37% Native American, 0.67% Asian, and 0.30% from two or more races. Hispanic or Latino of any race were 0.52% of the population.
There were 433 households out of which 42.7% had children under the age of 18 living with them, 71.6% were married couples living together, 3.5% had a female householder with no husband present, and 18.5% were non-families. 14.3% of all households were made up of individuals and 5.1% had someone living alone who was 65 years of age or older. The average household size was 3.09 and the average family size was 3.45.
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