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Elliott, Iowa

Elliott, Iowa
City
Location of Elliott, Iowa
Location of Elliott, Iowa
Coordinates: 41°8′56″N 95°9′43″W / 41.14889°N 95.16194°W / 41.14889; -95.16194Coordinates: 41°8′56″N 95°9′43″W / 41.14889°N 95.16194°W / 41.14889; -95.16194
Country  United States
State  Iowa
County Montgomery
Area
 • Total 0.42 sq mi (1.09 km2)
 • Land 0.42 sq mi (1.09 km2)
 • Water 0 sq mi (0 km2)
Elevation 1,073 ft (327 m)
Population (2010)
 • Total 350
 • Estimate (2012) 344
 • Density 833.3/sq mi (321.7/km2)
Time zone Central (CST) (UTC-6)
 • Summer (DST) CDT (UTC-5)
ZIP code 51532
Area code(s) 712
FIPS code 19-24915
GNIS feature ID 0456314

Elliott is a city in Montgomery County, Iowa, United States, along the East Nishnabotna River. The population was 350 at the 2010 census.

Elliott was founded in 1879.

Elliott is located at 41°8′56″N 95°9′43″W / 41.14889°N 95.16194°W / 41.14889; -95.16194 (41.149002, -95.162071).

According to the United States Census Bureau, the city has a total area of 0.42 square miles (1.09 km2), all of it land.

As of the census of 2010, there were 350 people, 147 households, and 95 families residing in the city. The population density was 833.3 inhabitants per square mile (321.7/km2). There were 168 housing units at an average density of 400.0 per square mile (154.4/km2). The racial makeup of the city was 99.1% White, 0.3% Native American, 0.3% Asian, and 0.3% from two or more races. Hispanic or Latino of any race were 0.9% of the population.

There were 147 households of which 31.3% had children under the age of 18 living with them, 51.7% were married couples living together, 9.5% had a female householder with no husband present, 3.4% had a male householder with no wife present, and 35.4% were non-families. 32.0% of all households were made up of individuals and 12.2% had someone living alone who was 65 years of age or older. The average household size was 2.38 and the average family size was 2.98.


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