Elliott, Iowa | |
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City | |
Location of Elliott, Iowa |
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Coordinates: 41°8′56″N 95°9′43″W / 41.14889°N 95.16194°WCoordinates: 41°8′56″N 95°9′43″W / 41.14889°N 95.16194°W | |
Country | United States |
State | Iowa |
County | Montgomery |
Area | |
• Total | 0.42 sq mi (1.09 km2) |
• Land | 0.42 sq mi (1.09 km2) |
• Water | 0 sq mi (0 km2) |
Elevation | 1,073 ft (327 m) |
Population (2010) | |
• Total | 350 |
• Estimate (2012) | 344 |
• Density | 833.3/sq mi (321.7/km2) |
Time zone | Central (CST) (UTC-6) |
• Summer (DST) | CDT (UTC-5) |
ZIP code | 51532 |
Area code(s) | 712 |
FIPS code | 19-24915 |
GNIS feature ID | 0456314 |
Elliott is a city in Montgomery County, Iowa, United States, along the East Nishnabotna River. The population was 350 at the 2010 census.
Elliott was founded in 1879.
Elliott is located at 41°8′56″N 95°9′43″W / 41.14889°N 95.16194°W (41.149002, -95.162071).
According to the United States Census Bureau, the city has a total area of 0.42 square miles (1.09 km2), all of it land.
As of the census of 2010, there were 350 people, 147 households, and 95 families residing in the city. The population density was 833.3 inhabitants per square mile (321.7/km2). There were 168 housing units at an average density of 400.0 per square mile (154.4/km2). The racial makeup of the city was 99.1% White, 0.3% Native American, 0.3% Asian, and 0.3% from two or more races. Hispanic or Latino of any race were 0.9% of the population.
There were 147 households of which 31.3% had children under the age of 18 living with them, 51.7% were married couples living together, 9.5% had a female householder with no husband present, 3.4% had a male householder with no wife present, and 35.4% were non-families. 32.0% of all households were made up of individuals and 12.2% had someone living alone who was 65 years of age or older. The average household size was 2.38 and the average family size was 2.98.