Cannon Ball, North Dakota
| Cannon Ball, North Dakota | |
|---|---|
| CDP | |
Cannon Ball River
|
|
 Location of Cannon Ball, North Dakota |
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| Country | United States |
| Indian Reservation | Standing Rock Indian Reservation |
| State | North Dakota |
| County | Sioux |
| Area | |
| • Total | 96.8 sq mi (251 km2) |
| • Land | 88.3 sq mi (229 km2) |
| • Water | 8.4 sq mi (22 km2) |
| Population (2010) | |
| • Total | 875 |
| • Density | 9.0/sq mi (3.5/km2) |
| Time zone | Central (CST) (UTC-6) |
| • Summer (DST) | CDT (UTC-5) |
Cannon Ball is a census-designated place (CDP) on the Standing Rock Indian Reservation, and in Sioux County, North Dakota in the United States. It is located in the northeastern part of Sioux County, having developed at the confluence of the Cannonball River and Lake Oahe of the Missouri River. The population was 875 at the 2010 census.
Cannon Ball is located at 46°14′58″N 100°38′19″W / 46.249361°N 100.638672°WCoordinates: 46°14′58″N 100°38′19″W / 46.249361°N 100.638672°W.
According to the United States Census Bureau, the CDP has a total area of 96.8 square miles (251 km2), of which, 88.3 square miles (229 km2) of it is land and 8.4 square miles (22 km2) of it (8.69%) is water.
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