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Battle of Tres de Abril

Battle of Tres de Abril
Revolt of Cebu
Part of the Philippine Revolution
Date 3–8 April 1898
Location Cebu, Cebu, Visayan Islands, Spanish East Indies (now Philippines)
Result Spanish victory
Belligerents
Philippine revolution flag kkk1.svg Katipunan Spain Spanish Empire
Commanders and leaders
Spain Primo de Rivera
Strength
5,000 katipuneros 500 cazadores
1 gunboat
1 cruiser
Casualties and losses
unknown unknown

The Battle of Tres de Abril occurred in 3 April 1898, during the Philippine Revolution. It was fought in the city of Cebu, a month after the Revolt of Cebu began.

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At 5 AM on 4 April, the rebels drove the Governor, General Montero, and his Spanish volunteers into Fort San Pedro and took control of Cebu City.} When the gunboat Maria Cristina opened fire, the rebels retreated to the Chinese quarter of Lutao. On 7 April, 500 men of the 73rd Native Regiment and Spanish cazadores arrived under the command of General Tejeiro, and with the cruiser Don Juan de Austria, forcing the rebels to retreat to San Nicolas. The Spanish continued their pursuit of the rebels on 8 April into the mountain region.


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