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Alexandrovsk-Sakhalinsky District

Alexandrovsk-Sakhalinsky District
Александровск-Сахалинский район (Russian)
Location of Alexandrovsk-Sakhalinsky District (Sakhalin Oblast).svg
Location of Alexandrovsk-Sakhalinsky District in Sakhalin Oblast
Coordinates: 50°54′N 142°09′E / 50.900°N 142.150°E / 50.900; 142.150Coordinates: 50°54′N 142°09′E / 50.900°N 142.150°E / 50.900; 142.150
Alexandrovsk-Sakhalinsky District, Sakhalin Oblast, Russia - panoramio.jpg
Coastal landscape, Alexandrovsk-Sakhalinsky District
Aleksandrovsk.png
Flag of Aleksandrovsk-Sakhalinsky rayon (Sakhalin oblast).png
Coat of arms
Flag
Location
Country Russia
Federal subject Sakhalin Oblast
Administrative structure (as of December 2011)
Administrative center town of Alexandrovsk-Sakhalinsky
Inhabited localities:
Cities/towns 1
Rural localities 13
Municipal structure (as of July 2012)
Municipally incorporated as Alexandrovsk-Sakhalinsky Urban Okrug
Statistics
Area 4,777.4 km2 (1,844.6 sq mi)
Population (2010 Census) 2,791 inhabitants
• Urban 0%
• Rural 100%
Density 0.58/km2 (1.5/sq mi)
Time zone MAGT (UTC+11:00)
Official website
on

Alexandrovsk-Sakhalinsky District (Russian: Алекса́ндровск-Сахали́нский райо́н) is an administrative district (raion) of Sakhalin Oblast, Russia, one of the seventeen in the oblast. As a municipal division, it is incorporated as Alexandrovsk-Sakhalinsky Urban Okrug. It is located in the west of the oblast. The area of the district is 4,777.4 square kilometers (1,844.6 sq mi). Its administrative center is the town of Alexandrovsk-Sakhalinsky. Population (excluding the administrative center): 2,791 (2010 Census);4,687 (2002 Census);8,526 (1989 Census).


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