United States presidential election in West Virginia, 1992

United States presidential election in West Virginia, 1992

← 1988 November 3, 1992 1996 →
Nominee Bill Clinton George H.W. Bush Ross Perot Party Democratic Republican Independent Home state Arkansas Texas Texas Running mate Al Gore Dan Quayle Electoral vote 5 0 0 Popular vote 331,001 241,974 108,829 Percentage 48.4% 35.4% 15.9%
County Results   Clinton—>70%   Clinton—60-70%   Clinton—50-60%   Clinton—40-50%   Bush—40-50%   Bush—50-60%   Bush—60-70%   Bush—>70%   Perot—40-50%
President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

George H. W. Bush
Republican

Bill Clinton
Democratic

The 1992 United States presidential election in West Virginia took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

West Virginia was won by Governor Bill Clinton (D-Arkansas) with 48.41% of the popular vote over incumbent President George H.W. Bush (R-Texas) with 35.39%. Businessman Ross Perot (I-Texas) finished in third with 15.92% of the popular vote. Clinton ultimately won the national vote, defeating incumbent President Bush.