United States presidential election in Rhode Island, 1992

United States presidential election in Rhode Island, 1992

← 1988 November 3, 1992 1996 →
Nominee Bill Clinton George H.W. Bush Ross Perot Party Democratic Republican Independent Home state Arkansas Texas Texas Running mate Al Gore Dan Quayle Electoral vote 4 0 0 Popular vote 213,299 131,601 105,045 Percentage 47.0% 29.0% 23.2%
County Results   Clinton—40-50%
President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

George H. W. Bush
Republican

Bill Clinton
Democratic

The 1992 United States presidential election in Rhode Island took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Rhode Island was won by Governor Bill Clinton (D-Arkansas) with 47.04% of the popular vote over incumbent President George H.W. Bush (R-Texas) with 29.02%. Businessman Ross Perot (I-Texas) finished in third with 23.16% of the popular vote. Clinton ultimately won the national vote, defeating incumbent President Bush.