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United States presidential election in Pennsylvania, 1840

United States presidential election in Pennsylvania, 1840
Pennsylvania
← 1836 October 30 – December 2, 1840 1844 →
  WHenryHarrison.png MartinVanBuren.png
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote 30 0
Popular vote 144,010 143,676
Percentage 50.00% 49.88%

President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig


Martin Van Buren
Democratic

William Henry Harrison
Whig

The 1840 United States presidential election in Pennsylvania took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose 30 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted for the Whig candidate, William Henry Harrison, over the Democratic candidate, Martin Van Buren. Harrison won Pennsylvania by a margin of 0.12%.


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