United States presidential election in New Hampshire, 1992

United States presidential election in New Hampshire, 1992

← 1988 November 3, 1992 1996 →
Nominee Bill Clinton George H. W. Bush Ross Perot Party Democratic Republican Independent Home state Arkansas Texas Texas Running mate Al Gore Dan Quayle Electoral vote 4 0 0 Popular vote 209,040 202,484 121,337 Percentage 38.9% 37.7% 22.6%
County Results   Clinton—40-50%   Bush—<40%   Bush—40-50%
President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

George H. W. Bush
Republican

Bill Clinton
Democratic

The 1992 United States presidential election in New Hampshire took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

New Hampshire was won by Governor Bill Clinton (D-Arkansas) with 38.91% of the popular vote over incumbent President George H.W. Bush (R-Texas) with 37.69%. Businessman Ross Perot (I-Texas) finished in third with 22.59% of the popular vote. Clinton ultimately won the national vote, defeating incumbent President Bush.

Clinton's win marked the beginning of a dramatic shift in New Hampshire politics toward the Democratic Party. The state had previously been regarded as a conservative Republican bastion; just four years earlier Bush had carried the state with over 60% of the vote. But like the rest of New England, New Hampshire began trending hard toward the left in the 1990s, and since 1992 the state has voted Democratic in every presidential election except 2000.

News networks projected the elections in New Hampshire, Georgia, and New Jersey for Bill Clinton before getting results for either of the said states, all of which voted for Bill Clinton by less than 2.5%. Had Bush managed to win Georgia, New Jersey, and New Hampshire in 1992, their projections would have been inaccurate.