United States presidential election in Missouri, 1996

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November 5, 1996

2000 →


Nominee	Bill Clinton	Bob Dole	Ross Perot
Party	Democratic	Republican	Reform
Home state	Arkansas	Kansas	Texas
Running mate	Al Gore	Jack Kemp	Pat Choate
Electoral vote	11	0	0
Popular vote	1,025,935	890,016	217,188
Percentage	47.5%	41.2%	10.1%

County Results

Clinton—80-90%

Clinton—70-80%

Clinton—60-70%

Clinton—50-60%

Dole—40-50%

Dole—50-60%

President before election

Bill Clinton
Democratic

Elected President

Bill Clinton
Democratic

The 1996 United States presidential election in Missouri took place on November 5, 1996 as part of the 1996 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for President and Vice President.

Missouri was won by President Bill Clinton (D) over Senator Bob Dole (R-KS), with Clinton winning 47.54% to 41.24% by a margin of 6.3%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third with 10.06% of the popular vote. Since 1904, this state has been carried by the winner of the presidential election, with the exceptions of the elections of 1956, 2008, and 2012. This election is the most recent in which Missouri voted for the Democrat.

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