United States presidential election in Mississippi, 1992

United States presidential election in Mississippi, 1992

1988 ← November 3, 1992 → 1996

Nominee George H.W. Bush Bill Clinton Ross Perot Party Republican Democratic Independent Home state Texas Arkansas Texas Running mate Dan Quayle Al Gore Electoral vote 7 0 0 Popular vote 487,793 400,258 85,626 Percentage 49.7% 40.8% 8.7%

County Results   Clinton—>70%   Clinton—60-70%   Clinton—50-60%   Clinton—40-50%   Bush—40-50%   Bush—50-60%   Bush—60-70%   Bush—>70%   Perot—40-50%

President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

George H. W. Bush
Republican

Bill Clinton
Democratic

The 1992 United States presidential election in Mississippi took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

Mississippi was won by incumbent President George H.W. Bush (R-Texas) with 49.68% of the popular vote over Governor Bill Clinton (D-Arkansas) with 40.77%. Businessman Ross Perot (I-Texas) finished in third with 8.72% of the popular vote. Clinton ultimately won the national vote, defeating both incumbent President Bush and Perot.