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United States presidential election in Iowa, 2004

United States presidential election in Iowa, 2004
Iowa
← 2000 November 2, 2004 2008 →
  George-W-Bush.jpeg John F. Kerry.jpg
Nominee George W. Bush John Kerry
Party Republican Democratic
Home state Texas Massachusetts
Running mate Dick Cheney John Edwards
Electoral vote 7 0
Popular vote 751,957 741,898
Percentage 49.90% 49.23%

Iowa Presidential Election Results by Shaded County, 2004.svg
County Results
  Kerry—60-70%
  Kerry—50-60%
  Kerry—<50%
  Bush—<50%
  Bush—50-60%
  Bush—60-70%
  Bush—70-80%
  Bush—80-90%

President before election

George W. Bush
Republican

Elected President

George W. Bush
Republican


George W. Bush
Republican

George W. Bush
Republican

The 2004 United States presidential election in Iowa took place on November 2, 2004 throughout all 50 states and D.C., which was part of the 2004 United States presidential election. Voters chose 7 representatives, or electors to the Electoral College, who voted for President and Vice President.

Iowa was won by incumbent President George W. Bush by a 0.67% margin of victory, despite losing the state to Al Gore in 2000. Prior to the election, most news organizations considered this a swing state. The Democrats had won Iowa in the previous four presidential elections, though only narrowly in 2000. Gore had won the state by only 0.32%, a much weaker margin compared to 1988, when Democrat Michael Dukakis carried the state by 10 percentage points, and later when Democrat Bill Clinton won with a 6% margin in 1992 and a 10% margin in 1996. Iowa was one of just two states (along with New Mexico) to vote for Gore in 2000 but flip to Bush in 2004, although both times won by razor-thin margins.


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