United States presidential election in Iowa, 1996

United States presidential election in Iowa, 1996

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Nominee Bill Clinton Bob Dole Ross Perot Party Democratic Republican Reform Home state Arkansas Kansas Texas Running mate Al Gore Jack Kemp Patrick Choate Electoral vote 7 0 0 Popular vote 620,258 492,644 105,159 Percentage 50.26% 39.92% 8.52%
County Results   Clinton—30-40%   Clinton—40-50%   Clinton—50-60%   Clinton—60-70%   Dole—40-50%   Dole—50-60%   Dole—60-70%   Dole—70-80%
President before election Bill Clinton Democratic Elected President Bill Clinton Democratic

Bill Clinton
Democratic

Bill Clinton
Democratic

The 1996 United States presidential election in Iowa took place on November 7, 1996, as part of the 1996 United States presidential election. Voters chose 7 representatives, or electors to the Electoral College, who voted for President and Vice President.

Iowa was won by Democratic incumbent President Bill Clinton over Republican Senator Bob Dole of Kansas, with Clinton winning 50.26% of the vote to Dole's 39.92%, a margin of 10.34%. The Reform Party candidate, billionaire businessman Ross Perot, finished in third with 8.52% of the popular vote.

Iowa is one of thirteen states where on the election ballot, James Campbell of California, Perot's former boss at IBM, was listed as a stand-in Vice-Presidential candidate.