United States presidential election in Alabama, 1948

United States presidential election in Alabama, 1948

1944 ← November 2, 1948 → 1952

Nominee Strom Thurmond Thomas E. Dewey Party Dixiecrat Republican Home state South Carolina New York Running mate Fielding L. Wright Earl Warren Electoral vote 11 0 Popular vote 171,443 40,930 Percentage 79.75% 19.04%

County Results   Truman—>90%   Truman—80-90%   Truman—70-80%   Truman—60-70%   Truman—50-60%   Truman—40-50%   Truman—<40%   Dewey—<40%   Dewey—40-50%   Dewey—50-60%   Dewey—60-70%   Dewey—70-80%   Dewey—80-90%   Dewey—>90%   Thurmond—<40%   Thurmond—40-50%   Thurmond—50-60%   Thurmond—60-70%   Thurmond—70-80%   Thurmond—80-90%   Thurmond—>90%

President before election Harry S. Truman Democratic Elected President Harry S. Truman Democratic

Harry S. Truman
Democratic

Harry S. Truman
Democratic

In the United States presidential election of 1948, Alabama was the only state in which the National Democratic Party candidate, incumbent president Harry S. Truman, did not appear on the ballot. Instead, South Carolina governor Strom Thurmond obtained the official Democratic Party line, along with being considered the official Democratic nominee in Georgia, Louisiana, and Mississippi. In other southern states where he was on the ballot, Thurmond was forced to run under the label of the States' Rights Democratic Party.

Thurmond overwhelmingly won Alabama by a margin of 60.71%, or 130,513 votes, against his closest opponent, New York governor Thomas E. Dewey. Two third party candidates, Henry A. Wallace of the Progressive Party and Claude Watson of the Prohibition Party, appeared on the ballot in Alabama, though neither had any impact on the election there.