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29 of the 88 seats in the U.S. Senate (as well as special elections) 45 seats needed for a majority |
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Republican
Democratic
The United States Senate elections of 1892 and 1893 were elections which, corresponding with former Democratic President Grover Cleveland's return to power, had the Republican Party lose nine seats in the United States Senate and lose its majority to the Democratic Party. The Democratic majority, however, was minimal and didn't last past the next Congress.
As these elections were prior to ratification of the Seventeenth Amendment, Senators were chosen by State legislatures.
Senate Party Division, 53rd Congress (1893–1895)
In these elections the winners were seated during the 52nd Congress in 1892 or in 1893 before March 4; ordered by election date.
In this election, the winner was seated in the 53rd Congress, starting March 4, 1893.
In this election, the winner was seated in the 54th Congress, starting March 4, 1895.
In these general elections, the winners were elected for the term beginning March 4, 1893; ordered by state.
All of the elections involved the Class 1 seats.
In these elections, the winners were elected in 1893 after March 4, and seated in the 53rd Congress.
In this election, the winner was seated in the 54th Congress, starting March 4, 1895.
The New York election was held on January 18, 1893, by the New York State Legislature.
Republican Frank Hiscock had been elected to this seat in 1887, and his term would expire on March 3, 1893.
At the controversial State election in November 1891, 17 Democrats, 14 Republicans and 1 Independent were elected for a two-year term (1892-1893) in the State Senate. This was the only time a Democratic majority was seated in the State Senate between 1874 and 1910. At the State election in November 1892, 74 Democrats and 54 Republicans were elected for the session of 1893 to the Assembly. The 116th New York State Legislature met from January 3 to April 20, 1893, at Albany, New York.