United States House of Representatives elections, 1960

1958 ←

November 8, 1960

→ 1962

All 437 seats to the United States House of Representatives 219 seats were needed for a majority

	Majority party	Minority party

Leader	Sam Rayburn	Charles Halleck
Party	Democratic	Republican
Leader's seat	Texas-4th	Indiana-2nd
Last election	283 seats	153 seats
Seats won	262	175
Seat change	21	22
Popular vote	35,112,332	28,750,866
Percentage	54.8%	44.8%
Swing	1.2%	1.2%

Speaker before election

Sam Rayburn
Democratic

Elected Speaker

Sam Rayburn
Democratic

The 1960 United States House of Representatives elections was an election for the United States House of Representatives in 1960, which coincided with the election of President John F. Kennedy and was the first house election to feature all 50 U.S. states. In spite of Kennedy's victory, his Democratic Party lost 20 seats to the Republican Party. That may have been a reaction to the major Democratic gains in the previous election. An end to the economic downturn of the mid-1950s was also a factor. Still, the Democrats retained a clear majority in the House.

There were 437 seats: 435 from the reapportionment in accordance with 1950 census, and 1 seat for each of the new states of Alaska and Hawaii.

Notable freshmen included future Senate Majority Leader and presidential candidate Bob Dole (R-Kan.) and future independent presidential candidate John B. Anderson (R-Ill.).

Source: Election Statistics - Office of the Clerk

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