Trent, South Dakota
| Trent, South Dakota | |
|---|---|
| Town | |
 Location in Moody County and the state of South Dakota |
|
| Coordinates: 43°54′25″N 96°39′17″W / 43.90694°N 96.65472°WCoordinates: 43°54′25″N 96°39′17″W / 43.90694°N 96.65472°W | |
| Country | United States |
| State | South Dakota |
| County | Moody |
| Incorporated | 1884 |
| Area | |
| • Total | 1.04 sq mi (2.69 km2) |
| • Land | 1.04 sq mi (2.69 km2) |
| • Water | 0 sq mi (0 km2) |
| Elevation | 1,503 ft (458 m) |
| Population (2010) | |
| • Total | 232 |
| • Estimate (2012) | 234 |
| • Density | 223.1/sq mi (86.1/km2) |
| Time zone | Central (CST) (UTC-6) |
| • Summer (DST) | CDT (UTC-5) |
| ZIP code | 57065 |
| Area code(s) | 605 |
| FIPS code | 46-63940 |
| GNIS feature ID | 1258600 |
Trent is a town in Moody County, South Dakota, United States. The population was 232 at the 2010 census.
Trent was laid out in 1874.
Trent is located at 43°54′25″N 96°39′17″W / 43.90694°N 96.65472°W (43.906818, -96.654698), along the Big Sioux River.
According to the United States Census Bureau, the town has a total area of 1.04 square miles (2.69 km2), all of it land.
Trent has been assigned the ZIP code 57065 and the FIPS place code 63940.
As of the census of 2010, there were 232 people, 102 households, and 61 families residing in the town. The population density was 223.1 inhabitants per square mile (86.1/km2). There were 113 housing units at an average density of 108.7 per square mile (42.0/km2). The racial makeup of the town was 91.4% White, 0.9% African American, 3.4% Native American, 0.9% Asian, and 3.4% from two or more races. Hispanic or Latino of any race were 0.4% of the population.
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