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Shueyville, Iowa

Shueyville, Iowa
City
Shueyville iowa.jpg
Location of Shueyville, Iowa
Location of Shueyville, Iowa
Coordinates: 41°50′53″N 91°38′55″W / 41.84806°N 91.64861°W / 41.84806; -91.64861Coordinates: 41°50′53″N 91°38′55″W / 41.84806°N 91.64861°W / 41.84806; -91.64861
Country  United States
State  Iowa
County Johnson
Area
 • Total 1.79 sq mi (4.64 km2)
 • Land 1.79 sq mi (4.64 km2)
 • Water 0 sq mi (0 km2)
Elevation 801 ft (244 m)
Population (2010)
 • Total 577
 • Estimate (2012) 610
 • Density 322.3/sq mi (124.4/km2)
Time zone Central (CST) (UTC-6)
 • Summer (DST) CDT (UTC-5)
FIPS code 19-72840
GNIS feature ID 0461591

Shueyville is a city in Johnson County, Iowa, United States. It is part of the Iowa City, Iowa Metropolitan Statistical Area. The population was 577 at the 2010 census.

Shueyville is located at 41°50′53″N 91°38′55″W / 41.84806°N 91.64861°W / 41.84806; -91.64861 (41.848155, -91.648679).

According to the United States Census Bureau, the city has a total area of 1.79 square miles (4.64 km2), all of it land.

As of the census of 2010, there were 577 people, 204 households, and 173 families residing in the city. The population density was 322.3 inhabitants per square mile (124.4/km2). There were 210 housing units at an average density of 117.3 per square mile (45.3/km2). The racial makeup of the city was 97.1% White, 0.3% African American, 0.2% Native American, 1.4% Asian, and 1.0% from two or more races. Hispanic or Latino of any race were 1.0% of the population.

There were 204 households of which 42.6% had children under the age of 18 living with them, 78.9% were married couples living together, 3.9% had a female householder with no husband present, 2.0% had a male householder with no wife present, and 15.2% were non-families. 10.8% of all households were made up of individuals and 1.5% had someone living alone who was 65 years of age or older. The average household size was 2.83 and the average family size was 3.06.


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