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Oxford, Iowa

Oxford, Iowa
City
View of Oxford from 295th St
View of Oxford from 295th St
Location of Oxford, Iowa
Location of Oxford, Iowa
Coordinates: 41°43′22″N 91°47′23″W / 41.72278°N 91.78972°W / 41.72278; -91.78972Coordinates: 41°43′22″N 91°47′23″W / 41.72278°N 91.78972°W / 41.72278; -91.78972
Country  United States
State  Iowa
County Johnson
Area
 • Total 0.91 sq mi (2.36 km2)
 • Land 0.91 sq mi (2.36 km2)
 • Water 0 sq mi (0 km2)
Elevation 751 ft (229 m)
Population (2010)
 • Total 807
 • Estimate (2012) 821
 • Density 886.8/sq mi (342.4/km2)
Time zone Central (CST) (UTC-6)
 • Summer (DST) CDT (UTC-5)
ZIP code 52322
Area code(s) 319
FIPS code 19-60645
GNIS feature ID 0459975

Oxford is a city in Johnson County, Iowa, United States. It is part of the Iowa City, Iowa Metropolitan Statistical Area. The population was 807 at the 2010 census.

Oxford was platted in 1868. It is named from Oxford Township, which takes its name from Oxford, New York.

Oxford is located at 41°43′22″N 91°47′23″W / 41.72278°N 91.78972°W / 41.72278; -91.78972 (41.722645, -91.789841).

According to the United States Census Bureau, the city has a total area of 0.91 square miles (2.36 km2), all of it land.

As of the census of 2010, there were 807 people, 336 households, and 216 families residing in the city. The population density was 886.8 inhabitants per square mile (342.4/km2). There were 350 housing units at an average density of 384.6 per square mile (148.5/km2). The racial makeup of the city was 92.9% White, 3.3% African American, 1.5% Asian, 0.1% from other races, and 2.1% from two or more races. Hispanic or Latino of any race were 2.4% of the population.


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