Oak Grove Township, Benton County, Indiana
| Oak Grove Township | |
|---|---|
| Township | |
 Location of Oak Grove Township in Benton County |
|
| Coordinates: 40°31′09″N 87°15′54″W / 40.51917°N 87.26500°WCoordinates: 40°31′09″N 87°15′54″W / 40.51917°N 87.26500°W | |
| Country | United States |
| State | Indiana |
| County | Benton |
| Organized | July 1840 |
| Government | |
| • Type | Indiana township |
| Area | |
| • Total | 35.53 sq mi (92.0 km2) |
| • Land | 35.51 sq mi (92.0 km2) |
| • Water | 0.02 sq mi (0.05 km2) |
| Elevation | 748 ft (228 m) |
| Population (2010) | |
| • Total | 1,581 |
| • Density | 44.5/sq mi (17.2/km2) |
| Time zone | EST (UTC-5) |
| • Summer (DST) | EDT (UTC-4) |
| FIPS code | 18-55620 |
| GNIS feature ID | 453681 |
Oak Grove Township is one of eleven townships in Benton County, Indiana. As of the 2010 census, its population was 1,581 and it contained 705 housing units. It was one of the first three townships originally created by the county's commissioners in 1840. It takes its name from White Oak Grove which grew southwest of Oxford.
According to the 2010 census, the township has a total area of 35.53 square miles (92.0 km2), of which 35.51 square miles (92.0 km2) (or 99.94%) is land and 0.02 square miles (0.052 km2) (or 0.06%) is water.
The township contains two cemeteries: Justus and Oxford.
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