Lake Harbor, Florida
| Lake Harbor, Florida | |
|---|---|
| CDP | |
| Coordinates: 26°41′13″N 80°48′27″W / 26.68694°N 80.80750°WCoordinates: 26°41′13″N 80°48′27″W / 26.68694°N 80.80750°W | |
| Country |
 United States
|
| State |
 Florida
|
| County | Palm Beach |
| Area | |
| • Total | 1.3 sq mi (3.4 km2) |
| • Land | 1.3 sq mi (3.4 km2) |
| • Water | 0.0 sq mi (0.0 km2) |
| Elevation | 13 ft (4 m) |
| Population (2000) | |
| • Total | 195 |
| • Density | 148.7/sq mi (57.4/km2) |
| Time zone | Eastern (EST) (UTC-5) |
| • Summer (DST) | EDT (UTC-4) |
| ZIP code | 33459 |
| Area code(s) | 561 |
| FIPS code | 12-38000 |
| GNIS feature ID | 0285247 |
Lake Harbor is a census-designated place (CDP) in Palm Beach County, Florida, United States. The population was 195 at the 2000 census. It located along the southern banks of Lake Okeechobee, at the beginning of the Miami Canal. John Stretch Park is also located alongside the north end of Lake Harbor and the lake.
Lake Harbor is located at 26°41′13″N 80°48′27″W / 26.68694°N 80.80750°W (26.686985, -80.807613).
According to the United States Census Bureau, the CDP has a total area of 3.4 km² (1.3 mi²), all land.
As of the census of 2000, there were 195 people, 65 households, and 44 families residing in the CDP. The population density was 57.5/km² (148.7/mi²). There were 118 housing units at an average density of 34.8/km² (90.0/mi²). The racial makeup of the CDP was 41.54% White (35.9% were Non-Hispanic White,) 42.56% African American, 3.08% Asian, 2.05% from other races, and 10.77% from two or more races. Hispanic or Latino of any race were 6.67% of the population.
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