June Park, Florida
| June Park, Florida | |
|---|---|
| Census-designated place | |
 Location in Brevard County and the state of Florida |
|
| Coordinates: 28°4′25″N 80°41′9″W / 28.07361°N 80.68583°WCoordinates: 28°4′25″N 80°41′9″W / 28.07361°N 80.68583°W | |
| Country |  United States of America |
| State |
 Florida
|
| County |
 Brevard
|
| Area | |
| • Total | 3.4 sq mi (8.8 km2) |
| • Land | 3.4 sq mi (8.8 km2) |
| • Water | 0 sq mi (0 km2) |
| Elevation | 26 ft (8 m) |
| Population (2010) | |
| • Total | 4,094 |
| • Density | 1,200/sq mi (470/km2) |
| Time zone | Eastern (EST) (UTC-5) |
| • Summer (DST) | EDT (UTC-4) |
| FIPS code | 12-35800 |
| GNIS feature ID | 0284977 |
June Park is a census-designated place (CDP) in Brevard County, Florida. The population was 4,094 at the 2010 United States Census. It is part of the Palm Bay–Melbourne–Titusville Metropolitan Statistical Area.
June Park is located at 28°4′25″N 80°41′9″W / 28.07361°N 80.68583°W (28.073643, -80.685709).
According to the United States Census Bureau, the CDP has a total area of 3.4 square miles (8.8 km2), all of it land.
As of the census of 2000, there were 4,367 people, 1,736 households, and 1,274 families residing in the CDP. The population density was 1,171.0 people per square mile (452.0/km²). There were 1,859 housing units at an average density of 498.5/sq mi (192.4/km²). The racial makeup of the CDP was 96.86% White, 0.76% African American, 0.16% Native American, 1.21% Asian, 0.14% from other races, and 0.87% from two or more races. Hispanic or Latino of any race were 2.29% of the population.
...
Wikipedia