Indian Rocks Beach, Florida | |
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City | |
Location in Pinellas County and the state of Florida |
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Coordinates: 27°53′45″N 82°50′51″W / 27.89583°N 82.84750°WCoordinates: 27°53′45″N 82°50′51″W / 27.89583°N 82.84750°W | |
Country | United States |
State | Florida |
County | Pinellas |
Area | |
• Total | 1.4 sq mi (3.6 km2) |
• Land | 0.9 sq mi (2.4 km2) |
• Water | 0.5 sq mi (1.2 km2) |
Elevation | 9 ft (3 m) |
Population (2010) | |
• Total | 4,113 |
• Density | 2,900/sq mi (1,100/km2) |
Time zone | Eastern (EST) (UTC-5) |
• Summer (DST) | EDT (UTC-4) |
ZIP codes | 33785-33786 |
Area code(s) | 727 |
FIPS code | 12-33625 |
GNIS feature ID | 0284535 |
Website | www |
Indian Rocks Beach is a city in Pinellas County, Florida, United States. The population was 4,113 at the 2010 census. Indian Rocks Beach is part of the Tampa-St. Petersburg-Clearwater, FL Metropolitan Statistical Area.
Indian Rocks Beach is located at 27°53′45″N 82°50′51″W / 27.89583°N 82.84750°W (27.895799, -82.847550). It lies on a barrier island between the Gulf of Mexico and the Intracoastal Waterway. It is north of Indian Shores and south of Belleair Shore and Belleair Beach. Tourism is its primary industry. It was incorporated in 1956.
According to the United States Census Bureau, the city has a total area of 1.4 square miles (3.6 km2), of which 0.9 square miles (2.3 km2) is land and 0.5 square miles (1.3 km2) (33.09%) is water.
As of the census of 2000, there were 5,072 people, 2,700 households, and 1,393 families residing in the city. The population density was 5,454.6 inhabitants per square mile (2,105.7/km²). There were 4,032 housing units at an average density of 4,336.1 per square mile (1,673.9/km²). The racial makeup of the city was 97.18% White, 0.30% African American, 0.18% Native American, 0.61% Asian, 0.02% Pacific Islander, 0.30% from other races, and 1.42% from two or more races. Hispanic or Latino of any race were 3.17% of the population.