Hobart Township, Lake County, Indiana
| Hobart Township | |
|---|---|
| Township | |
 |
|
| Coordinates: 41°32′48″N 87°15′53″W / 41.54667°N 87.26472°WCoordinates: 41°32′48″N 87°15′53″W / 41.54667°N 87.26472°W | |
| Country | United States |
| State | Indiana |
| County | Lake |
| Government | |
| • Type | Indiana township |
| Area | |
| • Total | 25.98 sq mi (67.3 km2) |
| • Land | 25.47 sq mi (66.0 km2) |
| • Water | 0.51 sq mi (1.3 km2) |
| Elevation | 627 ft (191 m) |
| Population (2010) | |
| • Total | 39,417 |
| • Density | 1,547.4/sq mi (597.5/km2) |
| FIPS code | 18-34132 |
| GNIS feature ID | 453414 |
Hobart Township is one of eleven townships in Lake County, Indiana. As of the 2010 census, its population was 39,417 and it contained 16,366 housing units.
According to the 2010 census, the township has a total area of 25.98 square miles (67.3 km2), of which 25.47 square miles (66.0 km2) (or 98.04%) is land and 0.51 square miles (1.3 km2) (or 1.96%) is water.
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