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Hartsville, New York

Hartsville, New York
Town
Hartsville, New York is located in New York
Hartsville, New York
Hartsville, New York
Location within the state of New York
Coordinates: 42°14′50″N 77°41′34″W / 42.24722°N 77.69278°W / 42.24722; -77.69278
Country United States
State New York
County Steuben
Area
 • Total 36.2 sq mi (93.7 km2)
 • Land 36.2 sq mi (93.7 km2)
 • Water 0.0 sq mi (0.0 km2)
Elevation 2,116 ft (645 m)
Population (2000)
 • Total 585
 • Density 16.2/sq mi (6.2/km2)
Time zone Eastern (EST) (UTC-5)
 • Summer (DST) EDT (UTC-4)
FIPS code 36-32567
GNIS feature ID 0979055

Hartsville is a town in Steuben County, New York, United States. The population was 585 at the 2000 census. The town is named after a prominent early settler, Reuben Hart.

The Town of Hartsville is on the county's western border and is south of Hornell, New York.

The first permanent settler arrived around 1810. The early lumber industry gradually converted to raising dairy cows as land was cleared. The town was formed from the Town of Hornellsville in 1844.

According to the United States Census Bureau, the town has a total area of 36.2 square miles (94 km2), of which, 36.2 square miles (94 km2) of it is land and 0.04 square miles (0.10 km2) of it (0.06%) is water.

The western town line is the border of Allegany County, New York.

To the west is the Town of Alfred in Allegany County. To the north is the Town of Hornellsville and to the south is the Town of Greenwood. The eastern town line is shared with the Town of Canisteo.

As of the census of 2000, there were 585 people, 233 households, and 170 families residing in the town. The population density was 16.2 people per square mile (6.2/km²). There were 377 housing units at an average density of 10.4 per square mile (4.0/km²). The racial makeup of the town was 99.49% White, 0.17% Native American, 0.17% from other races, and 0.17% from two or more races. Hispanic or Latino of any race were 0.17% of the population.


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