Falman-County Acres, Texas | |
---|---|
former CDP | |
Coordinates: 27°55′31″N 97°10′3″W / 27.92528°N 97.16750°WCoordinates: 27°55′31″N 97°10′3″W / 27.92528°N 97.16750°W | |
Country | United States |
State | Texas |
County | San Patricio |
Area | |
• Total | 0.2 sq mi (0.6 km2) |
• Land | 0.2 sq mi (0.6 km2) |
• Water | 0.0 sq mi (0.0 km2) |
Population (2000) | |
• Total | 289 |
• Density | 1,170.7/sq mi (452.0/km2) |
Time zone | Central (CST) (UTC-6) |
• Summer (DST) | CDT (UTC-5) |
FIPS code | 48-25398 |
Falman-County Acres is a census-designated place (CDP) in San Patricio County, Texas, United States. The population was 289 at the 2000 census.
The Falman-County Acres CDP was deleted in the 2010 census and parts taken to form Country Acres and Falman CDPs.
Falman-County Acres is located at 27°55′31″N 97°10′3″W / 27.92528°N 97.16750°W (27.925416, -97.167400).
According to the United States Census Bureau, the CDP has a total area of 0.2 square miles (0.52 km2), all land.
As of the census of 2000, there were 289 people, 95 households, and 76 families residing in the CDP. The population density was 1,170.7 people per square mile (446.3/km²). There were 100 housing units at an average density of 405.1/sq mi (154.4/km²). The racial makeup of the CDP was 92.73% White, 1.38% African American, 4.84% from other races, and 1.04% from two or more races. Hispanic or Latino of any race were 18.69% of the population.