Dennehotso, Arizona | |
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Census-designated place | |
Location in Apache County and the state of Arizona |
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Location in the United States | |
Coordinates: 36°50′14″N 109°51′39″W / 36.83722°N 109.86083°WCoordinates: 36°50′14″N 109°51′39″W / 36.83722°N 109.86083°W | |
Country | United States |
State | Arizona |
County | Apache |
Area | |
• Total | 10.0 sq mi (25.8 km2) |
• Land | 10.0 sq mi (25.8 km2) |
• Water | 0.0 sq mi (0.0 km2) |
Elevation | 5,015 ft (1,529 m) |
Population (2010) | |
• Total | 746 |
• Density | 75/sq mi (28.9/km2) |
Time zone | MST (UTC-7) |
• Summer (DST) | MDT (UTC-6) |
ZIP code | 86535 |
Area code | 928 |
FIPS code | 04-18580 |
GNIS feature ID | 0003954 |
Dennehotso (Navajo: Deinihootso) is a census-designated place (CDP) in Apache County, Arizona, United States. The population was 746 at the 2010 census.
Dennehotso is located at 36°50′14″N 109°51′39″W / 36.83722°N 109.86083°W (36.837286, -109.860884).
According to the United States Census Bureau, the CDP has a total area of 10.0 square miles (25.8 km2), all of it land.
As of the census of 2000, there were 734 people, 168 households, and 141 families residing in the CDP. The population density was 73.8 people per square mile (28.5/km²). There were 233 housing units at an average density of 23.4/sq mi (9.1/km²). The racial makeup of the CDP was 98.64% Native American, 0.82% White, and 0.54% from two or more races. 0.27% of the population were Hispanic or Latino of any race.
There were 168 households out of which 56.5% had children under the age of 18 living with them, 55.4% were married couples living together, 24.4% had a female householder with no husband present, and 15.5% were non-families. 14.9% of all households were made up of individuals and 5.4% had someone living alone who was 65 years of age or older. The average household size was 4.37 and the average family size was 4.92.