CONCACAF Champions' Cup 1997
| Tournament details | |
|---|---|
| Host country | United States |
| City | Washington, D.C. |
| Dates | 13 August – 24 August |
| Teams | 8 (from 6 associations) |
| Final positions | |
| Champions |
 Cruz Azul (5th title)
|
| Runners-up |
 Los Angeles Galaxy
|
| Tournament statistics | |
| Matches played | 8 |
| Goals scored | 27 (3.38 per match) |
The 1997 CONCACAF Champions' Cup was the 33rd edition of the annual international club football competition held in the CONCACAF region (North America, Central America and the Caribbean), the CONCACAF Champions' Cup. It determined that year's club champion of association football in the CONCACAF region.
The teams were split into 3 zones (North, Central and Caribbean). The North American zone qualified 3 teams direct into the quarterfinals and 2 teams played a play-off to get a 4th spot in the quarterfinals. The Central American zone played a regional tournament to get 3 spots in the quarterfinal. The winner of the Caribbean zone got a place in the quarterfinals.
1997 was the first year that teams from the United States' premier league, Major League Soccer, took part in the Champions' Cup. The competitors in the MLS Cup, both winner and runner-up, were each given berths in the tournament.
All but two of the eight games played in the final tournament were played in Washington, D.C.. The final was won by Cruz Azul, who captured their fifth Champions' Cup title with a 5-3 victory over the Los Angeles Galaxy.
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