CONCACAF Champions' Cup 1996
| Tournament details | |
|---|---|
| Host country | Guatemala |
| City | Guatemala City |
| Dates | 15 July – 20 July |
| Teams | 4 (from 3 associations) |
| Final positions | |
| Champions |
 Cruz Azul (4th title)
|
| Runners-up |
Club Necaxa
|
| Tournament statistics | |
| Matches played | 6 |
| Goals scored | 29 (4.83 per match) |
The 1996 CONCACAF Champions' Cup was the 32nd edition of the annual international club football competition held in the CONCACAF region (North America, Central America and the Caribbean), the CONCACAF Champions' Cup. It determined that year's club champion of association football in the CONCACAF region and was played from 9 March 1996 through 20 July 1997.
The teams were split into 2 zones (North/ Central and Caribbean). The North/Central zone was split into 3 groups, qualifying each winner to the final tournament. The winner of the Caribbean zone, earned a place in a playoff against the USA representative for a spot in the final tournament. All qualifying matches in the tournament were played under the home/away match system, while the final tournament was played in Guatemala City.
Club Deportivo Cruz Azul from Mexico won the final, its fourth CONCACAF championship.
First Round
Cruz Azul on bye to the Third round.
Second Round
Alajuelense on bye to the Fourth round.
Third Round
Fourth Round
First Round
Second Round
First Round
Second Round
Third Round
Final stage was played in Guatemala City, Guatemala.
July 15 - 20, 1997
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